import std.stdio;
auto foo() {
int n = 4;
return ()=>n;
}
void main( ) {
auto dg = foo();
auto fn1 = dg.funcptr;
auto fn2 = cast(int function(void*))fn1;
fn2(dg.ptr); // 1
fn1(); // 2
}
This program crashes with an access violation, because fn1 has the wrong type, and thus gets called with the wrong number of parameters. I'm not entirely sure what the correct type is, but I expect int function(void*), as it takes the context pointer as an additional parameter, and that is typed void*.
Comment #1 by yebblies — 2013-08-17T23:15:59Z
*** This issue has been marked as a duplicate of issue 2672 ***