Bug 1059 – String literal concatenated with array of chars - inconsistent behavior

char[] hi1 = "h" ~ "i"; //works char[] hi1 = "h" ~ ['i']; //works char[] hi2 = ['h'] ~ "i"; // semicolon expected, not '~' //found '~' instead of statement char[] hi3 = ['h'] ~ ['i'];// semicolon expected, not '~' //found '~' instead of statement All 4 case means the same and should behave the same way.

Update: This issue occurs only in initialization, normal assignment works. char[] hi = "h" ~ "i"; //works char[] hi1 = "h" ~ ['i']; //works char[] hi2 = ['h'] ~ "i"; // semicolon expected, not '~' //found '~' instead of statement char[] hi3 = ['h'] ~ ['i'];// semicolon expected, not '~' //found '~' instead of statement hi1 = "h" ~ ['i']; //works hi1 = ['h'] ~ "i"; //works hi1 = ['h'] ~ ['i']; //works

Annoying because this limits the use of array literals in templates, A doesn't compile in the following: //template A(char a, char b) { const char[] A = [a] ~ [b]; } template B(char[] a, char[] b) { const char[] B = a ~ b ; } void main() { // static assert (A!('a', 'b') == "ab"); static assert (B!("a", "b") == "ab"); static assert (['a'] ~ ['b'] == "ab"); }

The template issue can be worked around as well, replace [a,b,...] with (cast(typeof(a))[] ~ a ~ b ~ ...): template A(char a, char b) { const char[] A = cast(char[])[] ~ a ~ b; }

This one I haven't found a workaround for: template Id(char[] s) { const Id = s; } // succeed static assert (Id!("x" ~ "y") == "xy"); static assert (Id!(['x'] ~ ['y']) == "xy"); // fail static assert (Id!("x" ~ ['y']) == "xy"); static assert (Id!(['x'] ~ "y") == "xy"); The second two give errors of the form: asdf.d(7): Error: expression "x" ~ ['y'] is not a valid template value argument asdf.d(7): template instance asdf.Id!("x" ~ ['y']) error instantiating asdf.d(7): static assert ("x" ~ ['y'] == "xy") is not evaluatable at compile time

These cases work in the current compilers. (dmd1.068 & dmd2.053)