Bug 10794 – Unsynchronized access to data of syncronized class

Here is something similar to example from Alexandrescu's book (13.14.1 Temporary Protection == No Escape): import std.stdio; int* ptr; void sneaky(out int bar) { ptr = &bar; } synchronized class B { private int bar; public void foo() { sneaky(bar); } int getBar() { return bar; } void setBar(int b) { bar = b; } } void main() { auto b = new shared(B); b.setBar(5); b.foo(); *ptr = 6; writeln(*ptr); writeln(b.getBar()); } I just replaced 'ref' with 'out' and now it compiles fine. Is it suppose to work this way? I also wonder why we have to write 'new shared(NameOfClass)' when class is synchronized, although we can't create not shared instance of synchronized class. Was it designed to make code more explicit?

I cannot reproduce this. I am getting: test.d(15): Error: function `test.sneaky(out int bar)` is not callable using argument types `(shared(int))` test.d(15): cannot pass argument `this.bar` of type `shared(int)` to parameter `out int bar` Which is correct.