Bug 11954 – Function call in string mixin inside mixin template without return value mistaken as declaration

Example code: mixin template CallFkt() { mixin("testFkt();"); } void testFkt() { import std.stdio : writeln; writeln("Called"); } void main() { mixin CallFkt; } Output: /d534/f170.d(2): Error: function declaration without return type. (Note that constructors are always named 'this') /d534/f170.d(2): Error: no identifier for declarator testFkt() /d534/f170.d(11): Error: mixin f170.main.CallFkt!() error instantiating Expected output: Called Description: This code works when testFkt returns a value (int for example) and the call is assigned to a variable (mixin("int i = testFkt();"); for example).

Mixin templates can only contain declarations, not statements.

(In reply to comment #1) > Mixin templates can only contain declarations, not statements. To be more precise, mixin("testFkt();") is parsed as MixinDeclaraton: http://dlang.org/module#MixinDeclaration and it never be parsed as the MixinStatement: http://dlang.org/statement#MixinStatement