Bug 12540 – Algebraic recursive alias declaration when a class contains an Algebraic member that can accept itself

Status
RESOLVED
Resolution
WORKSFORME
Severity
normal
Priority
P2
Component
phobos
Product
D
Version
D2
Platform
All
OS
All
Creation time
2014-04-07T12:03:58Z
Last change time
2018-10-16T19:22:32Z
Assigned to
No Owner
Creator
Dylan Knutson

Comments

Comment #0 by tcdknutson — 2014-04-07T12:03:58Z
It's not possible to create an Algebraic alias which can take a class, where that class has the same algebraic type as a member. Example code: ``` import std.variant; alias SomeAlg = Algebraic!SomeClass; class SomeClass { SomeAlg entity; } void main() {} ``` Yielding the error: ``` /d519/f212.d(3): Error: alias f212.SomeAlg recursive alias declaration /opt/compilers/dmd2/include/std/variant.d(1227): Error: template instance std.variant.maxSize!(SomeClass) error instantiating /d519/f212.d(3): instantiated from here: Algebraic!(SomeClass) /d519/f212.d(3): Error: template instance std.variant.Algebraic!(SomeClass) error instantiating ``` What's perhaps stranger is that this code does work: ``` import std.variant; //alias SomeAlg = Algebraic!SomeClass; class SomeClass { Algebraic!SomeClass entity; } void main() {} ``` But it's doing, as far as I can tell, the exact same thing.
Comment #1 by Jesse.K.Phillips+D — 2014-06-25T03:27:18Z
I think this is a duplicate of issue 10705.
Comment #2 by n8sh.secondary — 2018-10-16T19:22:32Z
Example code currently compiles & runs.