Bug 12592 – std.algorithm.keep to filter range elements and write back to the source range

Status
RESOLVED
Resolution
WORKSFORME
Severity
enhancement
Priority
P1
Component
phobos
Product
D
Version
D2
Platform
All
OS
All
Creation time
2014-04-18T11:03:54Z
Last change time
2018-03-31T13:45:06Z
Assigned to
No Owner
Creator
bearophile_hugs

Comments

Comment #0 by bearophile_hugs — 2014-04-18T11:03:54Z
This code uses ranges in a UFCS chain to compute the unique items of immutable data items, and to return an array (if you don't need r to be an array you can omit the last 'array' call): void main() { import std.array: array; import std.algorithm: sort, uniq, map; immutable data = [10, 3, 2, 3, 4, 10]; const int[] r = data.dup.sort().uniq.array; assert(r == [2, 3, 4, 10]); } But that allocates two arrays (beside the data), one in 'dup' and one in 'array'. To avoid that you can write: void main() { import std.algorithm: sort, uniq, copy; immutable data = [10, 3, 2, 3, 4, 10]; auto int[] r = data.dup.sort().release; r.length -= r.uniq.copy(r).length; assert(r == [2, 3, 4, 10]); } But: - This code is not very easy to write correctly the first time (I have had to compile and run it to be sure); - Its semantics and purpose are not as immediately clear for the reader as the first version; - Now r can't be const; - We have lost the nice single UFCS chain, and the code is longer. So a possible solution is to add a new function similar 'uniq' that performs that common operation (I don't know if release is needed here): void main() { import std.array: array; import std.algorithm: sort, uniq, map; immutable data = [10, 3, 2, 3, 4, 10]; const int[] r = data.dup.sort().release.keepUniq; assert(r == [2, 3, 4, 10]); } But that seems to contain a common pattern that perhaps it's worth generalizing, a pattern that is equally usable here too: const int[] r2 = data.dup.sort().filter!(x => x > 3).array; That could become: const int[] r2 = data.dup.sort().release.keepFilter!(x => x > 3); Generalizing it could become: const int[] r2 = data.dup.sort().release.keep!(filter!(x => x > 3)); And applied on the original code: const int[] r = data.dup.sort().release.keep!uniq; Another example: auto data2 = [10, 3, 2, 3, 4, 10]; data2 = data2.remove!(x => x > 3); assert(data2 == [3, 2, 3]); Becomes: data2.keep!(remove!(x => x > 3)); But this is not a good example because in my opinion it's much better to fix remove, see issue 10959 . If you have more usage cases please add them below.
Comment #1 by nick — 2014-07-06T11:51:49Z
I've written a similar function to keep(): https://github.com/ntrel/stuff/blob/master/refill.d My version isn't as easy to chain with UFCS as keep, but it does allow to refill a range from a different range altogether, rather than just a processed version of itself.
Comment #2 by nick — 2014-07-06T15:23:25Z
I just added an overload of refill so it can behave like your keep(): const r = data.dup.sort().release.refill!uniq;
Comment #3 by greensunny12 — 2018-02-10T20:18:25Z
We have group and filter, e.g. --- import std.stdio; void main() { import std.algorithm; immutable data = [10, 3, 2, 3, 4, 10]; assert(data.dup.sort.release.group.map!(a => a[0]).equal([2, 3, 4, 10])); } --- https://run.dlang.io/is/eBLeSa Closing as WORKSFORME. Plese reopen if you feel that filter and group don't work for or you have more arguments or examples.
Comment #4 by nick — 2018-02-12T16:25:17Z
> assert(data.dup.sort.release.group.map!(a => a[0]).equal([2, 3, 4, 10])); map does not produce an array, that's the idea. In fact using `group.map` is more complicated than just using `uniq`.