Bug 18770 – Ternary operator returns incorrect value when compiling with -O option

Code: import std.stdio; void main() { foreach (i; 0..2) { long x = (i % 2 == 0) ? 1 : -1; x.writeln; } } ----- Output (with -O option): 1 4294967295 ----- Output (without -O option): 1 -1 ----- It seems that -1 is implicitly converted to uint. As far as I tried, this behavior does not occur when... # type is int int x = (i % 2 == 0) ? 1 : -1 # negative value is on the left long x = (i % 2 == 0) ? -2 : -1 # condition can be evaluated at compile time(?) long x = false ? 1 : -1 All of the above correctly returns negative value with -O option.

I cannot reproduce this with the latest master. It seems that this has been fixed.