This C++ code:
------------------------------------------
template <typename T>
struct TemplateName
{
void fun() {}
};
template <template<typename> typename blah = TemplateName>
struct Str
{
using I = TemplateName<blah<int>>;
};
Str<>::I s;
------------------------------------------
Produces the symbol:
?fun@?$TemplateName@U?$TemplateName@H@@@@QEAAXXZ
The equivalent D code makes a mistake with the alias argument:
------------------------------------------
extern (C++)
struct TemplateName(T)
{
void fun();
}
extern (C++)
struct Str(alias blah = TemplateName)
{
alias I = TemplateName!(blah!int);
}
pragma(msg, Str!().I.fun.mangleof);
------------------------------------------
Prints:
?fun@?$TemplateName@U?$blah@H@@@@QEAAXXZ
Notice that the name of the alias parameter `blah` ends up in there, rather than the template it is an alias of?
Comment #1 by github-bugzilla — 2018-05-21T09:27:16Z