Bug 242 – template implicit template properties doesn't work

template x() { template x() { const x = 1; } } void main() { const y = x!()!(); } Gives: test.d(2): semicolon expected following auto declaration, not '!' test.d(2): found '!' instead of statement Instead, trying const y = x!().x!(), gives test.d(2): template identifier x is not a member of x I can't see any way to instantiate the inner template when it is "an implicit template property".

(In reply to comment #0) > template x() { template x() { const x = 1; } } > void main() { const y = x!()!(); } > > Gives: > test.d(2): semicolon expected following auto declaration, not '!' > test.d(2): found '!' instead of statement > > Instead, trying const y = x!().x!(), gives > > test.d(2): template identifier x is not a member of x > > I can't see any way to instantiate the inner template when it is "an implicit > template property". > Especially now with tuples, it would be nice if something like the x!()!() above worked. Because: * A template can only have one tuple parameter. * Multiple tuples passed into a tuple-taking template get merged into a single tuple. Thus nested tuple templates seems to be the best hope for writing algorithms that process or combine multiple tuples. template x(S...) { template x(T...) { /*use S and T together*/ } } x!(int,float)!(3,24.0) (And even if the inner one is not named x, you still can't do x!().y!() right now.)

This is an enhancement.

*** Issue 4061 has been marked as a duplicate of this issue. ***

*** Issue 4233 has been marked as a duplicate of this issue. ***