Bug 3055 – & operator doesn't get correct func to construct the delegate

Status
RESOLVED
Resolution
INVALID
Severity
normal
Priority
P2
Component
dmd
Product
D
Version
D2
Platform
Other
OS
Windows
Creation time
2009-06-06T19:36:00Z
Last change time
2015-06-09T01:27:45Z
Assigned to
nobody
Creator
davidl

Comments

Comment #0 by davidl — 2009-06-06T19:36:15Z
import std.stdio; class t { void func(){writefln("t");} void delegate() getdelegate(){return &t.func; } // this doesn't return the delegate of t.func } class v:t { void func(){writefln("v");} } class r:v { void func(){writefln("r");} void delegate() getdelegate(){return t.getdelegate(); } } void main() { r p= new r; p.getdelegate()(); } h3 gave me the solution which can work correctly: import std.stdio; class t { void func(){writefln("t");} void delegate() getdelegate(){ static void function() getfuncptr() { return &func; } auto res = &func; res.funcptr = getfuncptr; return res; } } class v:t { void func(){writefln("v");} } class r:v { void func(){writefln("r");} void delegate() getdelegate(){return t.getdelegate(); } } void main() { r p= new r; p.getdelegate()(); }
Comment #1 by maxim — 2013-05-22T09:15:28Z
Taking address of member function in the form of &A.foo yields as expected a function pointer, not delegate. To get delegate one need to omit class name.