Bug 8336 – Default function parameters ignored by delegate

Status
RESOLVED
Resolution
DUPLICATE
Severity
regression
Priority
P2
Component
dmd
Product
D
Version
D2
Platform
All
OS
All
Creation time
2012-07-02T05:00:00Z
Last change time
2012-07-02T08:34:37Z
Assigned to
nobody
Creator
puneet

Comments

Comment #0 by puneet — 2012-07-02T05:00:57Z
This code worked for version 2.059. But with the latest git pull, it does not compile, saying: test.d(5): Error: expected 1 function arguments, not 0 void callfoo(alias F, T) (T t) { typeof(&Foo.init.foo) dg; dg.funcptr = &F; dg.ptr = cast(void *)t; dg(); } class Foo { void foo(int n=2) {} } void main() { Foo f = new Foo(); callfoo!(Foo.foo)(f); }
Comment #1 by bearophile_hugs — 2012-07-02T05:09:54Z
Default arguments were never reliable for functions called trough a pointer, so this little change is expected, take a look at the changelog of 2.060alpha. I suggest to close this bug report...
Comment #2 by puneet — 2012-07-02T05:32:59Z
> Default arguments were never reliable for functions called trough a pointer, so > this little change is expected, take a look at the changelog of 2.060alpha. I think it would be cool if default arguments could be maintained for corresponding delegates too. I am too naive right now to find out which entry in the changelog are you pointing too. I tried but could not find anything obvious (to me).
Comment #3 by issues.dlang — 2012-07-02T08:34:37Z
Given how default arguments work, they make _no_ sense for either function pointers or delegates. All that happens with a default argument is that when you call the function, if you don't provide a value for the parameter with a default argument, the default argument is inserted for you. It's not part of the function's type. It doesn't result in multiple functions being declared. So, if you do void foo(int value = 5) {...} auto funcPtr = &foo; you've lost the information about the default argument. You simply have void function(int value) funcPtr; You could reassign it like so void bar(int number) {... } funcPtr = &bar; because the types are identical. The default argument has zero effect on the type. The situation does not change if you're dealing with a delegate rather than a function pointer. Function pointers and delegates just don't have anything to do with default arguments. There's further discussion on this in bug# 4208, which was ultimately closed as a duplicate of bug# 3646 - both of which relate to stuff compiling when it shouldn't due to issues with default arguments. *** This issue has been marked as a duplicate of issue 3646 ***