Bug 8579 – Default parameter appears a part of typeof().stringof of a function variable

This is related to bug 3866. import std.stdio; void func1(int i, double j = 1.0) { } void func2(int i, double j) { } void main() { auto fn1 = &func1; auto fn2 = &func2; assert(typeid(fn1) is typeid(fn2)); // Passes; fine. writeln(typeof(fn1).stringof); writeln(typeof(fn2).stringof); } The output includes the default value and for *both* of the variables: void function(int i, double j = 1) void function(int i, double j = 1) Interestingly, swap the definitions of fn1 and fn2, now neither has the default parameter value: auto fn2 = &func2; auto fn1 = &func1; Now the output: void function(int i, double j) void function(int i, double j) Ali

Here was a discussion (http://www.digitalmars.com/d/archives/digitalmars/D/What_to_do_about_default_function_arguments_164993.html) but seems the decision about default arguments was not made.

I think the decision has been made after that discussion: http://d.puremagic.com/issues/show_bug.cgi?id=3866#c5

Fixed commit: https://github.com/D-Programming-Language/dmd/commit/a711eb6b499ca85b7cfa4e758d9e968fef8d315f