Bug 9924 – Handy enum accessors

Status
RESOLVED
Resolution
INVALID
Severity
enhancement
Priority
P2
Component
phobos
Product
D
Version
D2
Platform
All
OS
All
Creation time
2013-04-11T17:20:00Z
Last change time
2013-04-12T05:34:04Z
Assigned to
nobody
Creator
bearophile_hugs

Comments

Comment #0 by bearophile_hugs — 2013-04-11T17:20:49Z
To better use enums I suggest to add to Phobos four small templates/functions like this (similar things are builtins in Ada): import std.conv: text; import std.traits: EnumMembers; template FirstMember(E) if (is(E == enum)) { enum FirstMember = EnumMembers!E[0]; } template LastMember(E) if (is(E == enum)) { enum LastMember = EnumMembers!E[$ - 1]; } E predMember(E)(E e) /*pure nothrow*/ if (is(E == enum)) in { assert(e != FirstMember!E); } body { switch (e) { foreach (i, e2; EnumMembers!E[1 .. $]) mixin("case E." ~ text(cast(E)e2) ~ ": return E." ~ text(cast(E)(EnumMembers!E[i])) ~ ";"); default: assert(0); } } E nextMember(E)(E e) /*pure nothrow*/ if (is(E == enum)) in { assert(e != LastMember!E); } body { switch (e) { foreach (i, e2; EnumMembers!E[0 .. $ - 1]) mixin("case E." ~ text(cast(E)e2) ~ ": return E." ~ text(cast(E)(EnumMembers!E[i + 1])) ~ ";"); default: assert(0); } } void main() { // Demo ----------------------- import std.stdio; enum Choice { rock, paper, scissors } static Choice whatBeats(in Choice ch) /*pure nothrow*/ { if (ch == LastMember!Choice) return FirstMember!Choice; else return nextMember(ch); } foreach (e; [EnumMembers!Choice]) writeln(e, " ", whatBeats(e)); writeln(predMember(Choice.paper)); writeln(predMember(Choice.scissors)); writeln(nextMember(Choice.rock)); writeln(nextMember(Choice.paper)); }
Comment #1 by bugzilla — 2013-04-11T18:04:42Z
I don't see much need for FirstMember and LastMember, just as I don't see a need for: E FirstElement(E)(E[] a) { return a[0]; } I believe such functions are trivia.
Comment #2 by bearophile_hugs — 2013-04-11T18:22:16Z
(In reply to comment #1) > I don't see much need for FirstMember and LastMember, just as I don't see a > need for: > > E FirstElement(E)(E[] a) { return a[0]; } > > I believe such functions are trivia. Maybe you are right, I am not sure. But note FirstElement is present in Phobos, it's named std.array.front: @property ref T front(T)(T[] a) if (!isNarrowString!(T[]) && !is(T[] == void[])) { assert(a.length, "Attempting to fetch the front of an empty array of " ~ T.stringof); return a[0]; }
Comment #3 by bearophile_hugs — 2013-04-11T18:51:20Z
If you remove FirstMember and LastMember the whatBeats() function: static Choice whatBeats(in Choice ch) /*pure nothrow*/ { if (ch == LastMember!Choice) return FirstMember!Choice; else return nextMember(ch); } Becomes: static Choice whatBeats(in Choice ch) /*pure nothrow*/ { if (ch == EnumMembers!Choice[$ - 1]) return EnumMembers!Choice[0]; else return nextMember(ch); } It's more noisy, and visually it's a little less easy to tell it's correct.
Comment #4 by bugzilla — 2013-04-11T19:37:02Z
(In reply to comment #2) > But note FirstElement is present in Phobos, it's named std.array.front: front() is there to support ranges, it is not a shorthand for [0].
Comment #5 by bugzilla — 2013-04-11T19:47:44Z
For similar reasons, I don't see a compelling case for nextMember or prevMember, either. I expect that an algorithm needing the next or previous member would be looping over EnumMembers!E[i] anyway. Such functions do not make code clearer, they obfuscate it behind trivia. The user wastes time wondering "should I use first(), or [0]? Why are there both? Is there a difference?" The documentation fills up with this pointless ephemera. A well designed interface should have a *minimum* of concepts and methods. They should ideally all be orthogonal, with zero overlap. I don't know Ada, but I suspect it has these methods because it does not have the [i] way of getting at enum members.
Comment #6 by bearophile_hugs — 2013-04-12T05:32:33Z
(In reply to comment #4) > front() is there to support ranges, it is not a shorthand for [0]. I don't agree. In the last year and half I have written two times by mistake: return items[$]; instead of: return items[$ - 1]; Now I usully use this, and avoid the problem, and it works even if later items becomes a range: return items.back;
Comment #7 by bearophile_hugs — 2013-04-12T05:33:38Z
(In reply to comment #5) > For similar reasons, I don't see a compelling case for nextMember or > prevMember, either. OK, I close this ER down.